-3p^2-225p+506250=0

Solution for -3p^2-225p+506250=0 equation:

-3p^2-225p+506250=0

a = -3; b = -225; c = +506250;
Δ = b2-4ac
Δ = -2252-4·(-3)·506250
Δ = 6125625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6125625}=2475$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-225)-2475}{2*-3}=\frac{-2250}{-6}
=+375
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-225)+2475}{2*-3}=\frac{2700}{-6}
=-450
$